Divide by 2
If the number is even, divide it by 2.
Example: 18 ÷ 2 = 9
A remarkably simple number game that leads to one of mathematics’ most intriguing unsolved questions.
Choose any positive whole number. Apply a simple rule to it, then apply the same rule to the new number. Keep repeating the process.
The Collatz Conjecture says that, no matter which positive whole number we start with, this process will eventually reach 1.
Once the sequence reaches 1, it enters a repeating cycle:
The problem is named after Lothar Collatz, a German mathematician who introduced the problem in 1937. It is also known as the 3n + 1 problem, because one of its rules is to multiply an odd number by 3 and add 1.
The word conjecture means a mathematical statement that appears to be true based on evidence, but has not yet been proved.
At every step, look at the number you currently have. There are only two possibilities:
If the number is even, divide it by 2.
Example: 18 ÷ 2 = 9
If the number is odd, multiply it by 3 and add 1.
Example: 7 × 3 + 1 = 22
Remember: After finding each new number, check whether it is even or odd. Then apply the appropriate rule again. Do not stop until the sequence reaches 1.
We begin with 6. Apply the correct rule at each step:
Conclusion: Starting with 6, the sequence reaches 1 after 8 steps.
Apply the rules repeatedly, checking each new number:
Conclusion: Starting with 7, the sequence also reaches 1. Notice that the numbers do not simply decrease at every step. Some become larger before eventually falling to 1.
| Starting Number | Steps to Reach 1 | Highest Number |
|---|---|---|
| 2 | 1 | 2 |
| 3 | 7 | 16 |
| 6 | 8 | 16 |
| 7 | 16 | 52 |
Different starting numbers can produce sequences of different lengths and reach different highest values. Yet these examples all reach 1. The conjecture asks whether this is true for every positive whole number.
Instructions: Start with the given positive whole number. Write every term in the sequence, show the rule used, and stop when you reach 1.
1. 4 → 2 → 1
2. 5 → 16 → 8 → 4 → 2 → 1
3. 9 → 28 → 14 → 7 → 22 → 11 → 34 → 17 → 52 → 26 → 13 → 40 → 20 → 10 → 5 → 16 → 8 → 4 → 2 → 1
4. 10 → 5 → 16 → 8 → 4 → 2 → 1
5. 12 → 6 → 3 → 10 → 5 → 16 → 8 → 4 → 2 → 1
6. 7 (14 ÷ 2). 7. 58 (19 × 3 + 1). 8. 52. 9. 8 steps. 10. Yes. For example, 3 and 6 both reach a highest value of 16.
11. No. For example, 3 → 10, so the value increases. 12. 15 → 46 → 23 → 70 → 35. 13. It has evidence from many examples, but it has not been proved for all positive whole numbers.
Try the process with a number of your choice. Does it reach 1? Can you prove that every positive whole number must eventually reach 1? Testing examples is useful, but a mathematical proof must explain why the statement is true for all permitted starting numbers.
Explore more Class 7 Mathematics tutorials, concept explanations and practice lessons on our YouTube channel.
SUBSCRIBE TO OUR YOUTUBE CHANNEL